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ΔMi−1 = −∂Σn=1NDi[n][Σj∈C{i}F[n − 1] + Fexti[[n−1]]


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ΔMi−1 = −∂Σn=1NDi[n][Σj∈C{i}F[n − 1] + Fexti[[n−1]]

 

"Lool at me I'm a pretentious cock." hihi ^_^'

Edited by vasio
  On 10/12/2009 at 10:37 PM, Calx Sherbet said:

um, nah.

 

i forgot questions are forbidden

 

oh that's not true. Just no questions about bands that play jazz music.

 

don't worry I still love you and will continue to provided that you admit that Manson has never exceeded A.S. in quality.

  On 10/12/2009 at 10:42 PM, Calx Sherbet said:

when did i say that

 

i love you too, you have nice legs

 

I never said you did. I was just saying.

 

And thank you. I wasn't aware you had seen my legs, but I've been told they are borderline perfect. My ass is a homo's dream also, as it is plump ghetto style (and I'm a small guy) and my grippers are still intact. Really, I guess I'm just a butterface.

Guest JohnTqs
  On 10/12/2009 at 10:50 PM, sneaksta303 said:
  On 10/12/2009 at 10:42 PM, Calx Sherbet said:

when did i say that

 

i love you too, you have nice legs

 

I never said you did. I was just saying.

 

And thank you. I wasn't aware you had seen my legs, but I've been told they are borderline perfect. My ass is a homo's dream also, as it is plump ghetto style (and I'm a small guy) and my grippers are still intact. Really, I guess I'm just a butterface.

 

lol

so wolfram alpha says its

 

F[n - 1]

 

EllipticF

EllipticF[Phi, m]

gives the elliptic integral of the first kind F(phi|m).

MORE INFORMATION

 

* Mathematical function, suitable for both symbolic and numerical manipulation.

 

* For -pi/2<phi<pi/2, .

 

* The complete elliptic integral associated with EllipticF is EllipticK.

 

* EllipticF is the inverse of JacobiAmplitude. If phi=am(u|m) then u=F(phi|m).

 

* EllipticF[Phi, m] has a branch cut discontinuity running along the ray from csc^2(phi) to infinity.

 

* For certain special arguments, EllipticF automatically evaluates to exact values.

 

* EllipticF can be evaluated to arbitrary numerical precision.

 

* EllipticF automatically threads over lists.

 

 

 

http://reference.wolfram.com/mathematica/ref/EllipticF.html

http://reference.wolfram.com/mathematica/tutorial/EllipticIntegralsAndEllipticFunctions.html

 

so thats it:

 

  Quote
The elliptic integral of the first kind EllipticF[Phi, m] is given for -Pi/2<Phi<Pi/2 by . This elliptic integral arises in solving the equations of motion for a simple pendulum. It is sometimes known as an incomplete elliptic integral of the first kind.

 

its to calculate a pendulum motion

Edited by o00o

wat?

 

just put the equation in wolfram alpha properly, it doesn't work like that

 

i mean look at it

 

this:

ΔMi−1 = −∂Σn=1NDi[n][Σj∈C{i}F[n − 1] + Fexti[[n−1]]

and this:

249cbf5d2e10dafde50f4b80e543e8d6.png

is not the same

 

it's like putting in 5-2 instead of 5-2

  On 10/13/2009 at 12:39 AM, o00o said:

http://reference.wolfram.com/mathematica/tutorial/EllipticIntegralsAndEllipticFunctions.html

 

so thats it:

 

  Quote
The elliptic integral of the first kind EllipticF[Phi, m] is given for -Pi/2<Phi<Pi/2 by . This elliptic integral arises in solving the equations of motion for a simple pendulum. It is sometimes known as an incomplete elliptic integral of the first kind.

 

its to calculate a pendulum motion

:facepalm:

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